Drupal 7.x

I am trying to exclude fields if they are empty, on the portfolio page I am creating with node--portfolio.tpl.php.  I have tried several variations including:

             <?php if (render($content['field_portfolio_video'])): ?>
                     <h5 class="mt-sm mb-xs"><?php print t('Related Videos'); ?></h5>
                     <?php print render($content['field_portfolio_video']); ?>
             <?php endif; ?>

and 

By default, Drupal prevents Googlebot for indexing comments URL by disallowing it in robots.txt as follows:

Disallow: /comment/reply/

Disallow: /?q=comment/reply/

But Google Webmasters Tools is reporting this as a problem. It reported a 2,066 blocked URLS on my site. As we all know, if there's something wrong with how Google is crawling our site, Adsense income is also being affected. So, how do you deal with this problem?

I want to create a view which filters on the parent taxonomy, but when a child taxonomy drills down to display only items with this child taxonomy.

Example:

- Jaguar
-- XJ
- Honda
- BMW

I have set up my view to use a contextual filter " Content: Has taxonomy term ID (with depth) " , so that the following works:

/Jaguar

This shows all (Jaguar & XJ)

However the following shows the same result:

/Jaguar/XJ

I want this Url to show only the "XJ" items. How do I go about doing this?

Hello, I have 0 experience with Drupal but was tasked with taking over a client's Drupal site to get their google maps integrated with their Google API key. I will do my best to explain my situation and hope that someone can help!

An example of the site in question is: https://www.fortressproperties.ca/property/details/strathcona-distributi...

You will see "This page can't load google maps correctly."

Drupal backend info:

Drupal Core: 7.33