By David Fiaty on

Hi,
I've created a custom block in Drupal 8 and I want to use it to display some node fields when the user is on the node page.
I've tried loading the node with the deprecated approach:

node_load($nid);

I can load any random node by it's id but if I try to load the currently viewed node, I get a blank page with no error in the logs.
Same result using the recommended approach. Any node works, but not the currently viewed node:

use Drupal\node\Entity\Node;
$node = Node::load($nid);

Why is Drupal 8 accepting to load any node in my block but not the one I'm currently viewing?
Thanks a lot for your answers.

⋅ Categories: Drupal 8.x

Comments

David Fiaty’s picture

David Fiaty commented

Or more precisely: what's the best approach to display some fields of the currently viewed node in a block in Drupal 8?

David Fiaty’s picture

David Fiaty commented

Just in case it makes a difference, I'm using a custom block with the PHP filter, not the templating system.

David Fiaty’s picture

David Fiaty commented

Ok, I now realise that what was giving me a blank page is trying to dump the node in the block with PHP.
The Drupal 8 code above works but trying var_dump($node) or print_r($node, 1) in the block will not work.
Thanks!

sprite’s picture

sprite commented

Rather than writing PHP, just create a View with a Block presentation and format the details to your liking.

spritefully yours
Technical assistance provided to the Drupal community on my own time ...
Thank yous appreciated ...

drupalfox’s picture

drupalfox commented

Check below module.

https://www.drupal.org/project/fieldblock