[solved] node id, and name in conditional snip

Hi,

I am using this snip Stefan Lehmann gave me here to have a different image based on node, problem is it works fine with the id, but a couple of the nodes are views, and one is contact, how do I declare those?

<?php 
$node = menu_get_object();
$menu_image = 'arrow_home.png';
if (!empty($node)) {
  $images = array(2 => 'arrow_home.png', 3 => 'arrow_formazione.png', 4 => 'arrow_workshop.png', 5 => 'arrow_raccontabito.png');
  $menu_image = isset($images[$node->nid]) ? $images[$node->nid] : $menu_image;
}
?>
<div class="fz-menu-bg">
<img src="/sites/all/themes/business/images/fz/<?php print $menu_image; ?>" />	
</div>

Thank you